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VB递归算法原理?

Private Sub Form_load() Dim i As Long,n as integer n=int(val(inputbox("输入Fibonacci数列的项数"))) For i = 1 To n Print Fibonacci(i) Next End Sub Private Function Fibonacci(n As Long)As Long If n = 1 Then Fibonacci = 1 ElseIf n...

Private Sub Form_load() Dim i As Long,n as integer n=int(val(inputbox("输入Fibonacci数列的项数"))) For i = 1 To n Print Fibonacci(i) Next End Sub Private Function Fibonacci(n As Long)As Long If n = 1 Then Fibonacci = 1 ElseIf n...

Function fun(n As Integer) As Long If n = 0 Or n = 1 Then fun = 1 Else fun = n * fun(n - 1) End IfEnd FunctionSub test() MsgBox fun(5)End Sub理解递归,不能从像一般函数那样用过程的方式来理解,而要用“功能”的方式去理解,如果你有面...

Form1上放一个文本框Text1, 一个按钮Command1。 在框中输入某个数字,例如10,代码会将列出f(1)至f(10)的值。 如果你只需要特定的第n项,比如第8项,就直接调用DiGui(8)即可。 代码: Private Sub Command1_Click() Dim n As Long n = CInt(Tex...

窗体中放入Text控件和命令按钮.取text中的数字作为N代码如下Private Function F(n As Long) As Long If n > 2 Then F = F(n - 1) + F(n - 2) Else F = 1 End If End FunctionPrivate Sub Command1_Click() Cls Dim I As Long I = Val(Text1.Text...

这实际上是一个排列组合里的分步法。下面的代码是用递归法来求,供参考: Sub main()Dim srcTxt$, myAry(), tmp, UB%'------原始数据输入到数组-----------srcTxt = "cap,tat,nbc-abc,mnt,xxs-oop"tmp = Split(srcTxt, "-")UB = UBound(tmp)ReDi...

Text1.Text = f(Val(Text1.Text)) 表示的意思是先把传入的文本字段Text1.Text 利用val 函数转化为int数值。然后调用自定义的递归函数 f (n as Integer) ,并把刚转化为int的数值作为参数传入其中,经过递归函数运算得到的结果作为返回值并赋值给...

代码具体不看了,因为没具体看d(x,y)的取值范围 假设他取值范围是1到14 那么表示,递归的层数是14层,然后每层中都有8个再次递归的函数 这就解释了为什么会溢出!我相信d(x,y)的值 8的14次方这根本不是电脑可以承受的 而且我相信d(x,y)取值数量极限...

Private Sub Command1_Click() Dim a As Integer, b As Integer a = Text1 b = Text2 Text3 = gcd(a, b) End Sub Function gcd(ByVal a As Integer, ByVal b As Integer) As Integer If a Mod b = 0 Then gcd = b Else gcd = gcd(b, a Mod b) En...

Private Sub Command1_Click() n = CInt(InputBox("N=")) y = fac(n) MsgBox n & "!=" & y End Sub Function fac(n) If n = 0 Or n = 1 Then fac = 1 Else fac = n * fac(n - 1) End Function

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